Задача 299. Janos Mikitovics - Fairy (Anti Take & Make, Take & Make, neutral Locust) |
(30.12.2013) Комбинация от фееричните условия Take & Make и Anti Take & Make с произвеждания и патови позиции с две свързани фигури. Добре дошъл на Janos Mikitovics от Унгария!
a) 1.Kb6 dxc8-a8L(bQc6) 2.Ba6 Lxc6-b5(bQb7) = b) 1.nLxd7-d7(wPd8L) Lxc8-a7(bQb8) 2.Ba8 cxb8-c8B(bQb7) = Double pins, self-blockades, L(B) - promotions. (Author) Take & Make: Every capture ("take") must be complemented by a further step ("make":not a capture) by the capturing piece, using the movement of the captured unit, otherwise the capture is illegal. Pawns may not end up on their own first rank. Captures on the promotion rank lead to promotions only if the pawn is still on the promotion rank after the "make" part of the move. Promotions at the end of the "make" element are normal. Anti Take & Make: every capture ("take") must be complemented by a further step ("make" - not a capture) by the captured piece (Kings excluded), which must move from its square of vanish (according to the wishes of the capturing side in case of options). The capture is forbidden if the captured unit have not possible move. Promotions at the end of the "make" element are normal. Locust (L): a piece which moves only to capture (on Queen lines). It lands on the next square behind the captured piece, but the arrival square must be empty. |
KOBULCHESS.COM
САЙТ ЗА ШАХМАТНА КОМПОЗИЦИЯ
Главен редактор:
Диян Костадинов
Помощник редактор:
Seetharaman Kalyan