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KoBulChess - 2012 ( 2)

2012: #2 - GM Milan Velimirovic IJ, #3 - FM Evgeny Fomichev IJ,

S# - GM Petko Petkov IJ, H# - IM Zoran Gavrilovski IJ,

- IM Manfred Rittirsch IJ

: Diyan Kostadinov IJ (email: Е-мейл адресът e защитен от спам ботове. s e-mail address is being protected from spambots. You need JavaScript enabled to view it // This e-mail address is being protected from spambots. You need JavaScript enabled to vie)


35) 1.Sfe5 Kb5 2.Be6 Rd7# [3.B:d7/S:d7(wK=rR)?? Self check]

1.Rc5 Kb3 2.Sd6 Be4# [3.Q:e4/S:e4(wK=rB)? Self check]

Specific KoBul Kings final positions, change of functions, white aristocrat (Diyan Kostadinov).

36) 1h1R 2.d8B Rh6 3.Bf6+ R:f6(wK=rB)#, 1h1Q 2.d8S Qh5 3.Sf7+ Q:f7(wK=rS)#

AUW, Meredith, white minimal (Authors)

37) a) 1.Kb6 Ga3 2.Ga6 Kc3 3.Kb5 Gd3# (4.K~,Gc4~??)

b) 1.Kc6 Ke7 2.Gf8 Kd8 3.Gc8 Kd7# (4.K~??)

Tanagra, black selfblocks (Author) Nice mates with paralised bK according Isardam rules (Diyan Kostadinov)


38) a) 1.AGb5(wAGc4) AGg4(wAGf4) 2.Ke7 AGc8(wSd7)

3.Bd6 Sf6 4.Kf8 AG4c7(wLd6)#

b) 1.AGf5(wAGf4) AGb4(wAGc4)+ 2. Kc7 AGd6(wSc5)

3.AGf4(wAGf5) AGc8(wSd7) 4. K:c8 AGg4(wAGf4)#

Very interesting initial position with black pieces only, which transforms into white during the solutions, Forsberg twins. It is nice example for Section B of the Alaikov 80 MT 2013 see announcement onhttp://kobulchess.com/en/tournaments/announcements/80-venelinalaikov.html(Diyan Kostadinov)

39) 1.BPg6-f7 2.SPe4:h7 3.BSPf3-a8=RH 4.BSPg2-b7 5.Kf3 6.BSPf2-a7 7.RHa8-a6 8.BSPa7-b8=RH 9.RHb8-b6 10.BSPb7-c8=RH 11.RHc8-c6 12.BPc7-d8=RH 13.RHd8-d6 14.BPd7-e8=RH junf415.RHe8-e6 16.BPe7-f8=RH 17.RHf8-f6 18.BPf7-g8=RH 19.RHg8-g6 20.BPg7-h8=RH 21.RHh8-h6 22.SPh7-h8=NH 23.NHb5 24.NHh2 25.Kg2 26.Kh3 Zugzwang 26RHg4 =

8 Rook-Hopper and 1 Nightrider-Hopper promotions, open of lines and very good fairy play a new great fairy seriesmover by the bulgarian maestro! The final position deserves a separate diagram. (Diyan Kostadinov)



41) 1.d2-d6 f7:a2 2.d:e7 a:b1Q! 3.c:d8S! Q:b2 4.S:b7 Q:b7 5.f2:a7 Qb7-d8 6.a:b8Q! Ra2 7.Qb3 Ba3 8.Q:g8+ Ra2:g8 9.R:a3 g7:g2 10.Rg3 d7:d1S! 11.Sf3 Qd2+ 12.Kf2 Sd1:f1 13.Sf3-e3 S:g3 14.Rd1 g2-e1S! 15.h2:g3 h7-h1B! 16.c2-h7 Qc2 17.Bd2 Sd3 18.Bd2:d3 Bc6 19.Be4 Bc6-c5 20.Be4-g5 Bf8.

Ceriani-Frolkin QSss, Phoenix-Pronkin qb. Quickly after publication of problem n.24, I found a cook: 12. g7:g1R! 13.h2-h3 Rg1-g2 14.Rf3:g2 Sh2 15.R1:h2. Here is the attempt of correction (Author). I really hope that this excellent problem is sound now. (Diyan Kostadinov)

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