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Problem 758.1: Zivko Janevski & Fadil Abdurahmanovic - Helpmate
zivko.janevskifadil.abdurahmanovic(29.12.2016) Fadil Abdurahmanovic joins Zivko to add a fourth pinmate to the already published original No.758.! An instructive example to new composers. 
 
 
 
 
 
 
 
758.1. Zivko Janevski (Macedonia)
& Fadil Abdurahmanovic (Bosnia and Herzegovina) 
 758.1
H#2        4 Sol.        (7+10)
  
1.Kd4 Rxc6 2.S2g3 Bxc3#
1.Kd3 Rb3 2.Sf6 Rxc3#
1.Rd4 Rf3 2.S4g3 Rxc3#
1.Bd4 h8Q 2.Be3 Qxc3#
 

A strong task of 4 pin mates on the same square c3 and 4 black interferences on the same line (h3-c3) by four different black pieces with organized disharmony! (Authors)    
 

Comments  

 
+1 #1 Seetharaman Kalyan 2016-12-29 03:50
Actually 757.1 published today is also another example to beginners on optimising the construction and improving it!
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+3 #2 Miodrag Mladenovic 2016-12-29 13:55
What a masterpiece! Beautiful problem.
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+3 #3 Velmurugan Nallusamy 2016-12-30 08:20
Very nice pin mates !
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