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Problem 939: Valery Shanshin - Twomover
valery.shansin(20.12.2018) The Russian grandmaster shows an excellent White correction and threat correction play in his nice twomover.
 
 
 
 
 
 
 
 
 
939. Valery Shanshin (Russia)
 939a
#2 vvvv                       (11+11)
 
   1.Re8? (A) – 2.Rxe7#
1…gxf5 2.Re3# (B)
1…Sfr (a) 2.Sg7#
1…Bd8!
 
   1.S~? – 2.Re3# (B)
1…d5! (b)
 
   1.Se3? – 2.Bd5#  (C) (2.Re3?)
1…Sf4! (a)
 
   1.Sxd6!? – 2.Re3# (B)
1…exd6 2.Re8# (A)
1…Bxd6 2.d8S#
1…b4!
 
   1.Sxe7! – 2.Re3#  (B(2.Bd5?)
1…d5 (b) 2.Bxd5# (C)
1…Kxe7 2.Re8# (A)
 
Choice play and Threat Correction (Author)
 
 

Comments  

 
0 #1 Seetharaman Kalyan 2018-12-21 17:27
At the request of the composer, I have replaced today, an improved version with the solution remaining the same. (In the previous diagram the Bc7 was promoted one, though permissible as per convention).
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0 #2 Vitaly Medintsev 2018-12-23 15:17
Actually, solution of improved version slightly differs in the first try.

The whole solution is the following:

1.Re8(A)? – 2.R:e7#
1…g:f5 2.Re3(B)#
1…Sf4(a) 2.Sg7#
1…Bd8!

1.S~? – 2.Re3(B)#
1…d5(b)!

1.Se3? – 2.Bd5(C)# (2.Re3?)
1…Sf4(a)!

1.S:d6!? – 2.Re3(B)#
1…e:d6 2.Re8(A)#
1…B:d6 2.d8S#
1…b4!

1.S:e7! – 2.Re3(B)# (2.Bd5?)
1…d5(b) 2.B:d5(C)#
1…K:e7 2.Re8(A)#
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0 #3 Seetharaman Kalyan 2018-12-23 18:55
Solution since corrected
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0 #4 Vitaly Medintsev 2018-12-23 20:30
Please, replace 1…Sfr with 1…Sf4 in the first try.
Quote
 

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