Problem 139*: Anton Bidlen - Fairy (Series H=) - Updated |
1.Bg7 2.Rf8 3.Be5 4.Rf6 5.Bc7 6.Ba5 7.Bb4 8.Ba3 9.Bc1 10.Be3 11.Bg1 12.Bxh2 13.Bg1 14.Be3 15.Bc1 16.Ba3 17.Bb4 18.Ba5 19.c4 20.Bd8+ Kxd8 = *The problem is cooked (see the comments below). Here is the improved version by Seetharaman Kalyan (India) which was partially check with help of Vaclav Kotesovec - thank you both!
1.Bg7 2.Rf8 3.Be5 4.Rf6 5.Bc7 6.Ba5 7.Bb4 8.Ba3 9.Bc1 10.Be3 11.Bxf2 12.Be3 13.Bc1 14.Ba3 15.Bb4 16.Ba5 17.Bc7 18.Be5 19.Rf8 20.Bg7 21.Rf6 22.Bh6 Rxh6= * Unfortunatelly this version is also cooked... For example: 1.gxf2 2.f1R 3.Rh1 4.Rxh2 5.Bg7 6.h6 7.hxg5 8.g4 9.g3 10.Rh4 11.Rg4 12.Bh6 13.Bg5 14.Bh4 15.g5 ~ = |
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Comments
01.Bh6-g7 02.c5-c4 03.Rf6-f8 04.Bg7-e5 05.Kd4-e3 06.Ke3-f2 07.Kf2-g1 08.Kg1xh2 09.Kh2-g1 10.Kg1-f2 11.Kf2-e3 12.Ke3-d4 13.Be5-g7 14.Rf8-f6 15.Bh8xg7=
But how the black can be stalemated after 13.h1R? Can you give us other moves too?
12. g:h2 13. h1R 14.h6 15.h:g5 17.g3 19.Rg4 20.Bh4 21.g5! any ! The moves are interchangeable of course.
So the version with movement of wR on h5,h4... etc. on the initial possition is useless...
In the partial computer check the problem was C+, but with the strict addition bPg3 to not move...
It does not solve in 15 moves, as white pawn f2 has to be removed for black to be stalemated (h6 pawn finally reaches g3). Black bishop cannot come through g5 shortcut to f2, because without WPg5 BPh6 cannot reach g3. So the cook is 22 moves long. Moving the white rook h2 to h3/h4 will produce other cooks. So it should be at h5 (allowing the black g6 pawn a capture to avoid cooks).
Ofcourse some moves can be in not the same order, but you got the point.
Sorry. You are right Diyan. I was still thinking on the lines of 1.g:h2 :( . Hope Mr.Anton can think of some way out.
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