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Problem 427 & 427.1: Alexey Oganesyan - Helpmate

oganesyan(21.07.2014) Helpmate moremover by the Russian composer Alexey Oganesyan.  His problem shows nice tempo promotions and excelsiors.

 

 

 

 

 

427. Alexey Oganesyan (Russia) 
21.07.2014
427
 H#4.5       1.2.1.1        (4+7)   
(This stipulation means that after the first move made by white, there are two variations)
 
 
1…e4
 
2.Bd5 exd5 3.Sc6 dxc6 4.Sb7 cxb7 5.d1B b8Q(B)#
 
2.Sf5 exf5 3.Sg6 fxg6 4.Bh7 gxh7 5.d1R h8Q(R)# 
 
Meredith. Two excelsiors. Tempo promotions. Black bishop phoenix. (Author). 
It is probably impossible to have a black rook (instead of one of knights) to show Black rook phoenix also due to cooks. (Seetharaman)
 
Based on comments received the author wants to publish the improved version of his problem.  This version has phoneix effect of both bishop and rook. 
 
427.1. Alexey Oganesyan (Russia)
22.07.2014
 427.1
H#4.5      1.2.1.1....        (4+7)
 
1…e4

2.Bd5 exd5 3.Rc6 dxc6 4.Sb7 cxb7 5.d1B b8Q(B)#

2.Sf5 exf5 3.Rg6 fxg6 4.Bh7 gxh7 5.d1R h8Q(R)# 

Meredith, Tempo promotions, excelsiors, bishop & rook phoenix. (Author)
 

Comments  

 
+2 #1 Nikola Predrag 2014-07-21 07:44
h#5 0.1.2.1.1.1.1.1.1.1.
For example bSd4 and bRa6 might add a Rook Phoenix
Quote
 
 
+2 #2 Aleksey Oganesjan 2014-07-21 09:07
Nikola, I have found the following version (with added Rook Phoenix) after your commenting:


h#4.5 1.2.1.1..
1...e4 2.Sf5 exf5 3.Rg6 fxg6 4.Bh7 gxh7 5.d1R h8Q(R)#
1...e4 2.Bd5 exd5 3.Rc6 dxc6 4.Sb7 cxb7 5.d1B b8Q(R)#

But I don't understand you about "h#5 0.1.2.1..." What do you want to say?
Quote
 
 
+1 #3 Aleksey Oganesjan 2014-07-21 09:34
Oh, excuse me, I understand now: "h#5 0.1.2.1..." is the same thing that "h#4.5 1.2.1.1..." :-)
Quote
 

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