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Originals - June 2012 (Part 1)

logo   Here are the KoBulChess Originals for June 2012. In this part are included twomovers, threemovers, helpmates and selfmates (fairies will be published in June Part 2). Welcome to Bosko Miloseski, Vito Rallo and Ivan Paskalev!





KoBulChess Originals - June 2012 (Part 1)

Judges for 2012: #2 - GM Milan Velimirovic IJ, #3 - FM Evgeny Fomichev IJ,

S# - GM Petko Petkov IJ, H# - IM Zoran Gavrilovski IJ,

Fairies - IM Manfred Rittirsch IJ

Editor: Diyan Kostadinov IJ (email: This e-mail address is being protected from spambots. You need JavaScript enabled to view it s e-mail address is being protected from spambots. You need JavaScript enabled to view it // This e-mail address is being protected from spambots. You need JavaScript enabled to vie)




25) 1...Ka2 2.Ra3#
   1.Qa7? Ra7!, 1.Qf8? Re7!, 1.Qd8? Rd7!, 1.Qg8? Rf7!
   1.Q:h2! (2.Bd5,Be4,Bf3,Bh3#), 1...Rd7/ Re7/ Rf7/ Rh7 2Bd5/ Be4/ Bf3/ Bh3#

Duel Q/R, duel R/B, battery mates, Fleck thema (Author) Meredith with duels in the tries and solution variations (Diyan Kostadinov)


26) 1…B:b5 x 2.Qb3# A (2.Qc4? C K:c4!; 2.Q:e4? B K:e4!), 1…Bc4 2.Qd6#, 1…Se5 2.Se7#


1…B:b5 x 2.Q:e4# B (2.Qb3? A Bc4!, 2.Qc4? C K:c4,B:c4!), but 1…Se5!

   1.Bg7?(2.Se7#), 1…Bc5 2.S:f4#, but 1…Sf6!

   1.Bd6?(2.Se7#) 1…R:h7!


1…B:b5 x 2.Qc4# C (2.Qb3? A Kc5!, 2.Q:e4? B Kc5!), 1…Se5 2.Se7#, 1…e5 2.g8Q#

Very interesting change of mates after 1…B:b5 with cyclic dual avoidance (Diyan Kostadinov)




27) 1.Sd4? (2.B:c2#), 1…c:d4!, 1.R:c5? (2.Bc2#), 1…d:c5!

     1.Rh5! (2.R:h7 ~ 3.Rh1#)

1…R:h5 2.Sd4 (3.Bc2#) 2…c:d4 3.Q:h5#, 1…Rd8 2.R:c5 (3.Bc2#) 2…d:c5 3.Q:d8#

(1…Rh5 2.R:h5…, 1…Rh8 2.R:h8/g:h8…)

Good logical style threemover by Nikolay Dimitrov (Diyan Kostadinov)






28) a) 1.e1R h8S 2.Re3 Sg6# b) 1.e1B h8Q 2.Bg3 Qh6#

Allumwandlung, Model mates, capture free (Author) AUW, selfblocks and model mates (Diyan Kostadinov)


29) 1.Re5 Sb2 2.Be4 Se2#, 1.Bd3 f4 2.Re4 Sf5#

Grimshaw on e4 (Author) Grimshaw after critical moves, selfblocks. I hope the problem is not direct anticipated… (Diyan Kostadinov)


30) 1.Kf5 Bd2 2.Rf6 Ra5#, 1.Kf6 R:e4 2.Bf5 Bc3#

Very rich thematic complex – open of lines by bK after moves on thematic pin lines, selfblocks and line closing by thematic black B/R, change of functions – excellent helpmate! (Diyan Kostadinov)



31) a) 1.Kg5 Kd6 2.Kf5 Sf1 3.Ke4 Sfg3#, b) 1.Kf5 Kb4 2.Ke5 Sc3 3.Kd4 S:f3#

Miniature, exchange functions of white Ss, Ideal mates (Author) Clear realisation of the authots idea – Miniature and Ideal mates (Diyan Kostadinov)


32) a) 1.Bg8 Sf3 2.Kh7 S:g5+ 3.Kh6 Kh4 4.Bh7 Sf7#

     b) 1.g4 Kh4 2.g5+ Kh5 3.g6+ Kh6 4.Bg8 Be5#

Forsberg twins, white minimal, black selfblocks (Diyan Kostadinov)




33) 1.Rh1! Bа7 2.Rа1 Bb8 3.Rа8 Bа7 4.Rh8 Bb8 5.R:h4 Bа7 6.S:а7 b5 7.S:b5 R:h4#

Four corners play by wR (Diyan Kostadinov)



34) 1.Bb5+ Ke1 2.Qe3+ Kd1 3.Be2+ Ke1 4.Qc3+ Kf2 5.Bb5+ Kg1 6.Q:g3+ Kh1 7.Qf3+ Kg1 8.Se2+ Kh2 9.Sd4+ Kg1 10.Rb1+ Kh2 11.Qf2+ Kh3 12.Rb3+ Kg4 13.Qf5+ Kh4 14.Qf4+ Kh5 15.Be8+ Rf7+ 16.Kg8 Kg6 17.Kh8 Kh5 18.Rb5+ Kg6 19.Qe5 Kh6 20.Qd6+ Rf6 21.Qf8+ R:f8#

Creation of two white batteries, switchback of wB. The problem is not fully computer tested, so it is good challenge for the solvers (Diyan Kostadinov)


Your suggestions, comments and new originals are always welcome!



+3 #1 Antonio Garofalo 2012-07-16 07:51
33-Paskalev. The Bishop promoted is, in my opinion, a light weakness. It can be published, but it will have difficult to enter in award.
+2 #2 dkostadinov 2012-07-16 08:20
Yes, Antonio, I also think that such a kind of promoted Bishop (according to the pawns structure as in problem n.33) is a light weakness and can be accept. In my opinion the author of such a kind composition should try to avoid this "weakness", but it is not so big minus if it is not possible. Of course some composers and judges do not accept "promoted" piece of this kind. Its a matter of taste and different opinion...
+2 #3 dkostadinov 2012-07-19 07:28
I have received an email from Kenneth Solja with improved version of Paskalev's S#7 n.33 where the white Pe2 is not on its initial square and this avoid the wBg6 to be promoted. The position is the same as the original version but with following changes: wPe2>e4, wPd4>d2, +bPe5. Thank you Kenneth! He also noted that probably even better versions are possible. What the visitors think?
+1 #4 Kenneth Solja 2012-07-19 10:19
I know now that bPe5 is not needed, so only changes are wPe2>e4 and wPd4>d2, as Diyan has already informed.
+2 #5 dkostadinov 2012-07-19 11:03
The computer check shown that bPe5 is needed,because of duals. For example: 2.e5 Bb8 3.e6 Ba7 4.e7 Bb8 5.e8Q Ba7 6.Qh8 Bb8 7.Dh4+ T:h4#
Quoting Kenneth Solja:
I know now that bPe5 is not needed, so only changes are wPe2>e4 and wPd4>d2, as Diyan has already informed.
+1 #6 dkostadinov 2012-07-20 11:36
Problem n.34 is not full computer tested and this is good challenge for solvers ;)
+2 #7 Dmitri Turevski 2012-07-27 08:50
Unfortunately No 29 is in fact anticipated by handful of problems, the closest probably would be PDB P0561105
+1 #8 dkostadinov 2012-07-27 13:03
Thank you for the information Dmitri! It would be good help for the judge.

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