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Задача 278: S.K.Balasubramanian & Pierre Tritten - Fairy (Anti Circe Clone)

balasubramaniantritten(15.11.2013) Последно време наблюдаваме повишаваща популяризация на фееричното условие Anti Circe Clone. Това е един нов пример на S. K. Balasubramanian и Pierre Tritten.



 

278


a) 1.Kxb4(K=rR-h8) Kg7+ 2.rRh4 Bg3# [3.rRxf4(rR=rS-b8)??]

b) 1.Kxh2(K=rB-f8) Rb8+ 2.rBh6 Rh8# [3.rBxf4(rB=rS-b8)??]


Exchange of functions between wR & wB.

bK cannot capture wSf4 as the square on which bK will reappear is guarded by the checking piece.

Zilahi.

(Author)

 

Anti Circe Clone:A capturing piece (including King) takes the nature of the captured piece and then goes to its Circe rebirth square. The checking/mating piece do not take the nature of the King and its returning square is according its own nature.

 

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