Discuss Problem 619: Miodrag Mladenovic - Helpmate https://www.kobulchess.com/en/problems/originals-2015/870-miodrag-mladenovic-helpmate.html Mon, 12 Oct 2026 16:07:57 +0000 JComments https://www.kobulchess.com/en/problems/originals-2015/870-miodrag-mladenovic-helpmate.html#comment-6937 Seetharaman Kalyan Sat, 31 Oct 2015 08:00:57 +0000 https://www.kobulchess.com/en/problems/originals-2015/870-miodrag-mladenovic-helpmate.html#comment-6937 https://www.kobulchess.com/en/problems/originals-2015/870-miodrag-mladenovic-helpmate.html#comment-6936 Seetharaman Kalyan Sat, 31 Oct 2015 07:50:35 +0000 https://www.kobulchess.com/en/problems/originals-2015/870-miodrag-mladenovic-helpmate.html#comment-6936 https://www.kobulchess.com/en/problems/originals-2015/870-miodrag-mladenovic-helpmate.html#comment-6935 e6 -> f4 -> d3. The problem could be published as four twins with stipulation H#1.5. There are four model mates and all black and white moves are different. However it's paradox to have perpetuum mobile where bS is doing a real "merry-go-round" in both directions. It's also possible to show perpetuum mobile theme with two solutions and set play in some trivial positions with three solutions. For example: 3R4.8.1r6.3B4.KP1kPP2.6P1.3S4.8 (I am not sure how to place diagram here). Although this is the correct problem in my opinion it does not deserve publishing. I placed it here more to present this idea with three solutions.]]> Miodrag Mladenovic Sat, 31 Oct 2015 07:00:59 +0000 https://www.kobulchess.com/en/problems/originals-2015/870-miodrag-mladenovic-helpmate.html#comment-6935