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		<title>Problem 673: Alain Bienabe - Fairy (Back-Home)</title>
		<description>Discuss Problem 673: Alain Bienabe - Fairy (Back-Home)</description>
		<link>https://www.kobulchess.com/en/problems/originals-2015/916-alain-bienabe.html</link>
		<lastBuildDate>Sun, 11 Oct 2026 10:01:49 +0000</lastBuildDate>
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			<title>Nikola Predrag says:</title>
			<link>https://www.kobulchess.com/en/problems/originals-2015/916-alain-bienabe.html#comment-7065</link>
			<description><![CDATA[Many duals after 2...hxg3 are avoided, wK must move away from his home square while it is attacked by bS. In principle, a condition should be used for creating a content, not only for the cook-stopping. A content relies on the right choice so, 1...Kf2!(hxg3?) and 3.c1B!(c1Q?) present the choice motivated by the condition (or, the condition creates the motivation for the play). The mandatory 7.Rh1-h3 doesn't seem to create anything. The only legal move is not even a tempo-move. (But at least, Black can't waste a move by 4.Bb2/g5 g4 5.Bf6 g5 etc., because 8.Rh1-h7 would be illegal.) It's obvious from the definition that 6.h1Q & 8.Qh7 f8Q+ 9.Qg8! would be legal because the back-home move 9.Qh3 would be a selfcheck. However, the condition is quite tricky. For instance (if I remember well the explanation by the inventor), 1.f1S Kg1 2.Sg3 hxg3 3.c1Q Kh1! would not only be legal but mandatory, since 3.c1Q attacks only the square c2.]]></description>
			<dc:creator>Nikola Predrag</dc:creator>
			<pubDate>Fri, 25 Dec 2015 17:40:27 +0000</pubDate>
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			<title>Seetharaman Kalyan says:</title>
			<link>https://www.kobulchess.com/en/problems/originals-2015/916-alain-bienabe.html#comment-7064</link>
			<description><![CDATA[In this problem the fairy condition has been used for only for avoiding duals (3.c1Q? and 7.Rh4,h4?) - I suppose that is also justified.]]></description>
			<dc:creator>Seetharaman Kalyan</dc:creator>
			<pubDate>Fri, 25 Dec 2015 14:12:50 +0000</pubDate>
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