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Problem 460: Igor Kochulov - Fairy (Symmetry Circe, Maximummer)
kochulov(07.11.2014) After the publication of the article about Symmetry (Symmetrical) Circe by Sebastien Luce (to see it click HERE) I received this Help-Selfmate by Igor Kochulov where he combine the Symmetry Circe with Maximummer.

 

 

 

 

 

460

 

1.e6 Na8 2.Qg5+ Kxg5(Qb4) 3.Qf4+ Kxf4(Qc5)

4.Qe5+ Kf3 5.Qf6+ exf6(Qc3) 8.Kd4+ Nxe6(d3)#

Ideal mate (Author)

 

Maximummer: Black must play the geometrically longest move or may choose from among longest moves of equal length, distances being measured from the center of each square. Diagonal and oblique distances are measured from the orthogonal coordinates by using Pythagora’s theorem (take the square root of the sum of the squares of the orthogonal distances). All other orthodox chess rules apply.

Symmetry Circe: The captured unit (not King) reappear on a square which is determined symmetrically by the central point of the chessboard allowing rebirths all around the board. 

 

Comments  

 
+2 #1 Seetharaman Kalyan 2014-11-07 01:09
Nice sequence and ideal mate! I wonder if a black knight (instead of nightrider) would have been enough.
Quote
 
 
+2 #2 Paul Raican 2014-11-07 09:45
Good question! Yes, it is enough:
Pieces
White Pe6 Ke4 Qb1
Black Pe7 Sb6 Kg3 Sc2
Stipulation hs#5
Condition SymmetryCirce max C+
1.Ke4-d3 Sc2-e1+ 2.Qb1xe1[+bSd8]+ Kg3-f4 3.Qe1-e5+ Kf4-f3 4.Qe5-f6+ e7xf6[+wQc3] 5.Kd3-d4+ Sd8*e6[+wPd3]#
Quote
 

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